How do you solve $2 ln (3 - x) - 4 = 0$ $2 ln ( 3 - x ) - 4 = 0$ ?

Question

1434 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-21T20:57:59

$x = 3 - e^{2} = - 4.389$ $x=3-e^2=-4.389$

Take the $4$ $4$ and $2$ $2$ to the right:

$ln (3 - x) = \frac{4}{2} = 2$ $ln(3-x)=4/2=2$

Apply the definition of logarithm:

${log}_{a} x = b \to x = a^{b}$ $log_ax=b ->x=a^b$ here the base is the number $e$ $e$ :

$3 - x = e^{2}$ $3-x=e^2$

rearranging:
$x = 3 - e^{2} = - 4.389$ $x=3-e^2=-4.389$

How do you solve 2ln(3−x)−4=02 ln ( 3 - x ) - 4 = 0?