How do you solve #2 ln x = 1#?

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Answer 1 · 2015-12-10T23:46:24

#x = sqrt(e)#

Using the property that

#e^ln(x) = x#

we have

#2ln(x) = 1#

#=> ln(x) = 1/2#

#=> e^ln(x) = e^(1/2)#

#=> x = e^(1/2) = sqrt(e)#