How do you solve $3^x=14$ ?

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Answer 1 · 2015-02-04T20:21:48

The answer is: $ln14/ln3$ .

You have to put both members as argument of a logarithm, it's better in the $e$ base.

So:

$ln3^x=ln14rArrxln3=ln14rArrx=ln14/ln3$ .

How do you solve 3^x=143^x=14?