How do you solve #-2=-(n-8)#?

1 Answer
Apr 29, 2017

Answer:

See the solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(-1)# to eliminate the negative from each side of the equation while keeping the equation balanced:

#color(red)(-1) * -2 = color(red)(-1) * -(n - 8)#

#2 = n - 8#

Now, add #color(red)(8)# to each side of the equation to solve for #n# while keeping the equation balanced:

#2 + color(red)(8) = n - 8 + color(red)(8)#

#10 = n - 0#

#10 = n#

#n = 10#