Question

How do you solve `(2 (tan^2)x - 1)((tan^2)x +1) = 0`?

Answer 1

Solve `(2tan^2 x - 1)(tan^2 x + 1) = 0`

`x = +- 35^@18 + kpi`

Explanation:

The quantity (tan^2 x + 1) > 0 regardless of values of x.
(2tan^2 x - 1) = 0
`tan^2 x = 1/2`
`tan x = +- sqrt2/2`
a. tan x = sqrt2/2 --> arc `x = 35^@18 + kpi`
b. tan x = -sqrt2/2 --> arc x = - 35*@18 + kpi