Question

How do you solve `2\times ( 14-: 2)^{2} + 5\times 12`?

Answer 1

`158`

Explanation:

Always count the number of terms first.
Simplify each term, following the order of operations - brackets first,
the strongest to weakest :
Powers and roots, then multiply and divide.
Each term will simplify to a single number which are added or subtracted in the last step.

`[2xxcolor(red)((14-: 2))^2]color(blue)( + 5xx 12)" "larr` there are 2 terms

=`[2xxcolor(red)((7)^2)]color(white)(xxxxx)color(blue)( + 60)" "larr` keep them separate

=`" "color(red)(2xx49)color(white)(xxxx.x)color(blue)( + 60)`

=`color(white)(xxx)color(red)(98)color(white)(xxxxxx.x)color(blue)( + 60)" "larr` now add

=`" "158`

Answer 2

158

Explanation:

work:
2 x `(14/2)^2` + 5 x 12
2 x `(7)^2`+ 5 x 12
2 x (49) + 5 x 12
98 + 60
158

Answer 3

158

Explanation:

When dealing with a calculation involving ' mixed' operations we can use the acronym PEMDAS.

`P-"Parenthesis"to("brackets")`

`E-"Exponents"to"powers"`

`M-"Multiplication"`

`D-"Division"`

multiplication and division are of equal precedence.

`A-"Addition"`

`S-"Subtraction"`

Following this order on the given calculation.

`2xx(color(red)(7))^2+5xx12`

`=2xxcolor(blue)(49)+5xx12`

`=(color(magenta)(2xx49))+( color(magenta)(5xx12))`

`=98+60=158`