How do you solve #2/(x+1)=4/x#?

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Answer 1 · 2017-08-03T01:21:25

#x=-2#

Refer to the explanation for the process.

Solve:

#2/(x+1)=4/x#

Cross multiply each denominator by the numerator of the opposite fraction.

#2x=4(x+1)#

Expland.

#2x=4x+4#

Subtract #2x# from both sides.

#0=4x+4-2x#

Subtract #4# from both sides.

#-4=2x#

Divide both sides by #2#.

#-4/2=x#

Simplify.

#-2=x#

Switch sides.

#x=-2#