How do you solve #2/(x+1) + 5/(x-2)=-2#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer salamat Feb 7, 2017 #x=1/2 and -3# Explanation: #2/(x+1) + 5/(x-2) = -2# multiply with #(x+1)(x-2)# to both side. #2(x-2) + 5(x+1) = -2(x+1)(x-2)# #2 x-4+5 x+5=-2(x^2-x-2)# #7x+1=-2x^2+2x+4# move to one side. #2x^2+5x-3=0# #(2x-1)(x+3)=0# #x=1/2 and -3# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1076 views around the world You can reuse this answer Creative Commons License