# How do you solve -2(x+3)^2 + 7 = -25?

Oct 3, 2016

$x = - 1 \text{ or } x = - 7$

#### Explanation:

The usual approach with a quadratic equation is to make it
equal to 0. However, this one is a special case - there is no $x$ term.

First isolate the bracket:

$- 2 {\left(x + 3\right)}^{2} \textcolor{red}{+ 7} = - 25$

$- 2 {\left(x + 3\right)}^{2} = - 25 \textcolor{red}{- 7}$

$\textcolor{b l u e}{- 2} {\left(x + 3\right)}^{2} = - 32$

${\left(x + 3\right)}^{2} = \frac{- 32}{\textcolor{b l u e}{- 2}} = 16$

$x + 3 = \pm \sqrt{16}$

$x = + 4 - 3 = 1$

$x = - 4 - 3 = - 7$