Question

How do you solve `2^x = 3^(2x+5)`?

Answer 1

Refer to explanation

Explanation:

We take logarithms on both sides of the equations hence

#2^x=3^(2x+5)=>xlog2=(2x+5)log3=>xlog2-2xlog3=5log3=> x=(5log3)/(log2-2log3)#