How do you solve #2/(x+3) - 3/(4-x) =( 2x-2) /( x^2-x-12)#?

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Answer 1 · 2016-04-14T16:27:53

#x=-1#

#2/(x+3)-3/(4-x)=(2x-2)/(x^2-x-12)#

#2/(x+3)+3/(x-4)=(2x-2)/((x-4)(x+3))#

#(2(x-4)+3(x+3))/cancel(((x+3)(x-4)))=(2x-2)/cancel(((x-4)(x+3)))#

#2x-8+3x+9=2x-2#

#5x-2x=-2-1#

#3x=-3#

#x=-1#