Question

How do you solve `2^(x-3)>5`?

Answer 1

I found: `x>3+log_2(5)`

Explanation:

We can try taking the log of both sides (base `2`):
`log_2(2^(x-3))>log_2(5)`
applying the definition of log we get:
`x-3>log_2(5)`
rearrange:
`x>3+log_2(5)`
or:
`x>5.3219`