How do you solve #−2(x − 3) = −6#?

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Answer 1 · 2018-03-13T16:39:07

#x=6#

Assuming you mean solving this for #x#, you would first divide both sides of the equation by #-2#, leaving

#(x-3)=3#

Then you would add #3# to both sides. Therefore

#x=6#

Answer 2 · 2018-03-13T16:41:45

#color(magenta)(x=6#

#-2(x-3)=-6#

#-2x+6=-6#

#-2x=-6-6#

#-2x=-12#

#x=-12/-2#

#color(magenta)(x=6#

~Hope this helps! :)