How do you solve 2^x=3.7?

1 Answer
Oct 20, 2015

x=log3.7/(log2) or x~~1.89

Explanation:

take the log of both sides:

log2^x=log3.7

There is a rule that states that loga^b can be written as b*loga

xlog2=log3.7

x=log3.7/(log2) (you can use your calculator to solve this)

x~~1.89

Note:
You can also use ln instead of log; your answer should be the same either way