How do you solve #2^x=3^(x+1)#?

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How do you solve #2^x=3^(x+1)#?

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Answer 1 · 2015-06-09T07:32:35

The value of x is "-2.71".

Explanation:

#2^x=3^(x+1)#
Apply logarithm with base 10 on both sides.
#log2^x=log3^(x+1)#
xlog2=(x+1)log3
By substituting the values of log2 & log3 ,we can get x value

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How do you solve #2^x=3^(x+1)#?

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