How do you solve $2^x=4^(x+1)$ ?

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Answer 1 · 2015-08-22T13:41:46

Re-express the right hand side as $2^(2x+2)$ to find $x = -2$

$(a^b)^c = a^(bc)$ and $4 = 2^2$ , so...

$2^x = 4^(x+1) = (2^2)^(x+1) = 2^(2(x+1)) = 2^(2x+2)$

So $x = 2x+2$

Subtract $(x + 2)$ from both sides to get $x = -2$

How do you solve 2^x=4^(x+1)2^x=4^(x+1)?