Question

How do you solve `2^x=5`?

Answer 1

`x=log5/log2~~2.32`

Explanation:

Given'
`2^x=5`
Taking log of both sides
`=>log2^x=log5`
`=>xlog2=log5`
`=>x=log5/log2=0.6989/0.3010~~2.32`