How do you solve #2(x² – 66) = -13x#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Binayaka C. Jul 25, 2016 #x=11/2 or x =-12# Explanation: #2(x^2-66)= -13x or 2x^2+13x-132 =0 or 2x^2+24x-11x-132=0 or 2x(x+12)-11(x+12)=0 or (2x-11)(x+12)=0 :. (2x-11)=0 or (x+12)=0:. x=11/2 or x =-12#[Ans] Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1139 views around the world You can reuse this answer Creative Commons License