# How do you solve 2+(x-7)+4x-2x+(4x+4)2=-11x+14-2-6x(4-5)+13(x-5)-7?

Mar 18, 2018

$x = - 21$

#### Explanation:

$2 + \left(x - 7\right) + 4 x - 2 x + \left(4 x + 4\right) 2 = - 11 x + 14 - 2 - 6 x \left(4 - 5\right) + 13 \left(x - 5\right) - 7$

Let's handle all distributing first:

$2 + \textcolor{b l u e}{x} - 7 + \textcolor{b l u e}{2 x} + \textcolor{b l u e}{8 x} + 8 = \textcolor{b l u e}{- 11 x} + 14 - 2 \textcolor{b l u e}{- 24 x} + \textcolor{b l u e}{30 x} + \textcolor{b l u e}{13 x} - 65 - 7$

Combine all variable terms:

$11 x + 2 - 7 + 8 = 8 x + 14 - 2 - 65 - 7$

Combine all constants:

$11 x + 3 = 8 x - 60$

Subtract $8 x$ from both sides:

$3 x + 3 = - 60$

Subtract $3$ from both sides:

$3 x = - 63$

Divide both sides by $3$:

$x = \textcolor{g r e e n}{- 21}$