How do you solve #2+(x-7)+4x-2x+(4x+4)2=-11x+14-2-6x(4-5)+13(x-5)-7#?

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Answer 1 · 2018-03-18T04:40:27

#x = -21#

#2+(x-7)+4x-2x+(4x+4)2=-11x+14-2-6x(4-5)+13(x-5)-7#

Let's handle all distributing first:

#2+color(blue)(x)-7 +color(blue)(2x)+color(blue)(8x)+8 =color(blue)(-11x)+14-2color(blue)(-24x)+color(blue)(30x)+color(blue)(13x)-65-7#

Combine all variable terms:

#11x+2-7+8 = 8x+14-2-65-7#

Combine all constants:

#11x+3 = 8x-60#

Subtract #8x# from both sides:

#3x+3=-60#

Subtract #3# from both sides:

#3x = -63#

Divide both sides by #3#:

#x = color(green)(-21)#