Question

How do you solve `2+(x-7)+4x-2x+(4x+4)2=-11x+14-2-6x(4-5)+13(x-5)-7`?

Answer 1

`x = -21`

Explanation:

`2+(x-7)+4x-2x+(4x+4)2=-11x+14-2-6x(4-5)+13(x-5)-7`

Let's handle all distributing first:

`2+color(blue)(x)-7 +color(blue)(2x)+color(blue)(8x)+8 =color(blue)(-11x)+14-2color(blue)(-24x)+color(blue)(30x)+color(blue)(13x)-65-7`

Combine all variable terms:

`11x+2-7+8 = 8x+14-2-65-7`

Combine all constants:

`11x+3 = 8x-60`

Subtract `8x` from both sides:

`3x+3=-60`

Subtract `3` from both sides:

`3x = -63`

Divide both sides by `3`:

`x = color(green)(-21)`