How do you solve #2^(x-9) = 5 #? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Shwetank Mauria Aug 12, 2016 #x=11.3223# Explanation: As #2^(x-9)=5#, writing in logarithmic form we have #(x-9)=log_2(5)#, which can be also written as #(x-9)=log5/log2# = #0.6990/0.3010=2.3223# and #x=9+2.3223=11.3223# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 1200 views around the world You can reuse this answer Creative Commons License