# How do you solve (2-x)log4=(5-x)log2?

The answer is $x = - 1$
log(4)=$\log \left({2}^{2}\right)$=$2 \log \left(2\right)$
So, you can simplify $\log \left(2\right)$
You have the linear equation $4 - 2 x = 5 - x \implies x = - 1$