# How do you solve 2(y+2)+y=19-(2y+3)?

$2 y + 4 + y = 19 - 2 y - 3$
Isolate $y$ on the left and numbers on the right:
$2 y + y + 2 y = - 4 + 19 - 3$
$5 y = 12$
Divide by $5$ both sides to get:
$y = \frac{12}{5}$