# How do you solve 2(-y + 5) = -3y – 3?

Jul 27, 2015

You isolate $y$ on one side of the equation.

#### Explanation:

Your equation contains one variable, $y$, which means that, in order to solve for $y$, you must isolate it on one side of the equation.

To do that, get rid of the paranthesis first

$2 \left(- y + 5\right) = - 3 y - 3$

$- 2 y + 10 = - 3 y - 3$

Add $3 y$ to both sides of the equation to get

$- 2 y + 3 y + 10 = \textcolor{red}{\cancel{\textcolor{b l a c k}{3 y}}} - \textcolor{red}{\cancel{\textcolor{b l a c k}{3 y}}} - 3$

$y + 10 = - 3$

Finally, add $- 10$ to both sides of the equation

$y - \textcolor{red}{\cancel{\textcolor{b l a c k}{10}}} + \textcolor{red}{\cancel{\textcolor{b l a c k}{10}}} = - 3 - 10$

$y = \textcolor{g r e e n}{- 13}$

Check to see if the calculations are correct

$2 \cdot \left(- \left(\textcolor{g r e e n}{- 13}\right) + 5\right) = - 3 \cdot \left(- 13\right) - 3$

$2 \cdot 18 = 39 - 3$

$36 = 36$ $\to$ the solution is correct!