Your equation contains one variable, #y#, which means that, in order to solve for #y#, you must isolate it on one side of the equation.
To do that, get rid of the paranthesis first
#2(-y + 5) = -3y - 3#
#-2y + 10 = -3y -3#
Add #3y# to both sides of the equation to get
#-2y + 3y + 10 = color(red)(cancel(color(black)(3y))) - color(red)(cancel(color(black)(3y))) - 3#
#y + 10 = -3#
Finally, add #-10# to both sides of the equation
#y - color(red)(cancel(color(black)(10))) + color(red)(cancel(color(black)(10))) = -3 - 10#
#y = color(green)(-13)#
Check to see if the calculations are correct
#2 * (-(color(green)(-13)) + 5) = -3* (-13) - 3#
#2 * 18 = 39 -3#
#36 = 36# #-># the solution is correct!
