How do you solve $20 (100 - e^(x/2)) = 500$ ?

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Answer 1 · 2015-08-06T17:24:27

$x=log(5625)=3.75$ 2 d.p.

Rearrange the expression as follows:

$20(100-e^(x/2))=500$ => $e^(x/2)=75$

Take logarithms =f both sides:

$loge^(x/2)=x/2=log(75)$ => $x=2log(75)=log(75^2)=log(5625)$

How do you solve 20 (100 - e^(x/2)) = 50020 (100 - e^(x/2)) = 500?