Question

How do you solve `20 (100 - e^(x/2)) = 500`?

Answer 1

`x=log(5625)=3.75` 2 d.p.

Explanation:

Rearrange the expression as follows:

`20(100-e^(x/2))=500` => `e^(x/2)=75`

Take logarithms =f both sides:

`loge^(x/2)=x/2=log(75)` => `x=2log(75)=log(75^2)=log(5625)`