How do you solve #20-9x+x^2=0#?

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Answer 1 · 2016-08-31T16:28:37

x=5 or x=3

The first step is to factor:
#x^2 - 9x + 20 = 0 #
#(x-5) (x-4) = 0#

The second step is to set each factor to zero:
#x=5# or #x=3#

Answer 2 · 2016-08-31T16:32:30

#x=4# or #x=5#

The first step when solving for solutions is to factor the equation:
#x^2-9x+20=0#, which when factored will be: #(x-4)(x-5)=0#

The next step is to solve each for zero:
#(x-4)(x-5)=0#
#x=4# or
#x=5#