How do you solve #(-22+3x)/(3x+7)#=2#?

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Answer 1 · 2016-11-28T02:07:28

#x = -12#

First, multiply each side of the equation by (3x + 7) to eliminate the fraction:

#((3x + 7)*(-22 + 3x))/(3x + 7) = 2(3x + 7)#

#(cancel(3x + 7)*(-22 + 3x))/cancel(3x + 7) = 6x + 14#

#-22 + 3x = 6x + 14#

You can now complete this problem using the necessary mathematics to isolate and solve for #x#:

#-22 + 3x - 3x - 14 = 6x + 14 - 3x - 14#

#-22 - 14 = 6x - 3x#

#-36 = 3x#

#(-36)/3 = (3x)/3#

#-12 = x#