How do you solve 25< 2x + 3x + 5?

2 Answers
Nov 2, 2017

x > 4

Explanation:

To solve this inequality, you treat it as a regular equation.

25 < 2x + 3x + 5
25 < 5x + 5
20 < 5x
4 < x

So the answer would be any value greater than 4, or x>4.

Nov 2, 2017

x>4

Explanation:

Except in the case where you're multiplying or dividing both sides of an inequality by a negative number, you'd approach solving an inequality like you would any other algebraic equation.

25<2x+3x+5
25<5x+5 (combine like terms)
20<5x (subtract 5 from both sides)
4< x (divide both sides by 5 to isolate x)

x>4