How do you solve 25^ { x ^ { 2} - x } = 1?

1 Answer
Mar 25, 2017

x_1=0

x_2=1

Explanation:

Using the law of exponents, we know that the only exponent of 25 which yields an answer of 1 is 0. (log_(25)1=0)

Thus, x^2-x=0

x(x-1)=0

x=0

x-1=0

x=1