# How do you solve 25x^2 = 13  and simplify the answer in simplest radical form?

Sep 18, 2016

$x = + \frac{\sqrt{13}}{5} \text{ or } x = - \frac{\sqrt{13}}{5}$

#### Explanation:

The usual method of solving a quadratic is to make it equal to 0.
However, this is a special case because there is no term in x.

We can use the following method:

$25 {x}^{2} = 13 \text{ } \leftarrow$isolate the ${x}^{2}$

${x}^{2} = \frac{13}{25}$

$x = \pm \sqrt{\frac{13}{25}}$

$x = + \frac{\sqrt{13}}{5} \text{ or } x = - \frac{\sqrt{13}}{5}$