How do you solve #25x^2 = 13 # and simplify the answer in simplest radical form?

1 Answer
Sep 18, 2016

Answer:

#x = +(sqrt13)/5 " or " x = -(sqrt13)/5#

Explanation:

The usual method of solving a quadratic is to make it equal to 0.
However, this is a special case because there is no term in x.

We can use the following method:

#25x^2 = 13" "larr#isolate the #x^2#

#x^2 = 13/25#

#x = +-sqrt(13/25)#

#x = +(sqrt13)/5 " or " x = -(sqrt13)/5#