# How do you solve 25x^2-30x=-9?

May 3, 2016

$x = \frac{3}{5}$

#### Explanation:

Once you put all of the terms of the quadratic on one side of the equation, then you get a perfect square trinomial:

Add $9$ to both sides to get:

$0 = 25 {x}^{2} - 30 x + 9$

$= {\left(5 x\right)}^{2} - 2 \left(5 x\right) \left(3\right) + {3}^{2}$

$= {\left(5 x - 3\right)}^{2}$

So $x = \frac{3}{5}$