How do you solve $27^(x+2)=3$ ?

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Answer 1 · 2015-05-23T09:45:23

$27^(x+2)=3$

$27$ can be written as $(3)^3$

the expression now becomes:
$(3)^(3.(x+2)) = (3)^1$

equating exponents:
$3.(x+2) = 1$

$3x+6 = 1$

$x= -5/3$

How do you solve 27^(x+2)=327^(x+2)=3?