# How do you solve 27^(x+2)=3?

##### 1 Answer
May 23, 2015

${27}^{x + 2} = 3$

$27$ can be written as ${\left(3\right)}^{3}$

the expression now becomes:
${\left(3\right)}^{3. \left(x + 2\right)} = {\left(3\right)}^{1}$

equating exponents:
$3. \left(x + 2\right) = 1$

$3 x + 6 = 1$

$x = - \frac{5}{3}$