How do you solve 27^(x+2)=3?

May 20, 2016

Put in equal bases.

Explanation:

${\left({3}^{3}\right)}^{x + 2} = 3$

${3}^{3 x + 6} = {3}^{1}$

${3}^{3 x} = {3}^{1 - 6}$

${3}^{3 x} = {3}^{- 5}$

$x = - \frac{5}{3}$

Hopefully this helps!