# How do you solve 27x² - 12 = 0?

Jul 5, 2015

Get the ${x}^{2}$ by itself, then take square root of both sides.

#### Explanation:

$27 {x}^{2} - 12 = 0$
First, add 12 to both sides: $27 {x}^{2} = 12$
Second, divide both sides by 27: ${x}^{2} = \frac{12}{27}$
Third, reduce the fraction to lowest terms: ${x}^{2} = \frac{4}{9}$
Fourth, take $\pm$ the square root of both sides: $x = \pm \sqrt{\frac{4}{9}}$
Fifth, simplify the square roots: $x = \pm \frac{2}{3}$

The solution set is $\left[- \frac{2}{3} , \frac{2}{3}\right]$