How do you solve #27x² - 12 = 0#?

1 Answer
Andy Y.
Jul 5, 2015

Get the #x^2# by itself, then take square root of both sides.

Explanation:

#27x^2-12=0#
First, add 12 to both sides: #27x^2 = 12#
Second, divide both sides by 27: #x^2 = 12/27#
Third, reduce the fraction to lowest terms: #x^2 = 4/9#
Fourth, take #+-# the square root of both sides: #x=+-sqrt(4/9)#
Fifth, simplify the square roots: #x=+-2/3#

The solution set is #[-2/3, 2/3]#

Related questions
See all questions in Comparing Methods for Solving Quadratics
Impact of this question
5267 views around the world
You can reuse this answer
Creative Commons License