How do you solve #2abs(4x - 6) - 8 = 12#?

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Answer 1 · 2018-07-12T10:57:56

#x=-1# or #x=4#

#2|4x−6|−8=12#

#therefore 2|4x−6|=20#

#therefore |4x−6|=10#

Now, #|a|=b \iff a=\pm b#, so either

#4x-6=10 \iff 4x = 16 \iff x=4#

or

#4x-6 = -10 \iff 4x = -4 \iff x=-1#