Question

How do you solve `2cos3θ + 3 = 1` from `[0,2pi]`?

Answer 1

`theta = pi/3`

Explanation:

`2cos(3theta) + 3 = 1`

`rArr 2cos(3theta) = -2`

`rArr cos(3theta) = -1`

within the range `[0,2pi]`
`rArr 3theta = pi`
`color(white)("XXXX")`(this is a standard angle)

`rArr theta = pi/3`