Question

How do you solve `2cosx-sqrt3=0` and find all solutions in the interval `0<=x<360`?

Answer 1

`x=30^o and x=330^o`

Explanation:

`2cos x= sqrt3`
`cos x=sqrt3/2`
`alpha=cos^-1(sqrt3/2)`
`alpha=30^o`
Since basic angle is positive, it is in quadrant 1 and 2
`x=30^o and x=360-30^o`
`x=30^o and x=330^o`