# How do you solve 2e^(8x)=45?

Sep 30, 2016

${e}^{8 x} = \ln \left(\frac{45}{2}\right)$

${e}^{8 x} = 22.5$

$\ln \left({e}^{8 x}\right) = \ln 22.5$

$8 x \ln e = \ln 22.5$

$8 x = \ln 22.5$

$x = \ln \frac{22.5}{8}$

$x \cong 0.39$

Hopefully this helps!