Question

How do you solve `2h^2-h-3=0`?

Answer 1

`h=color(blue)(1 1/2)`
or
`h=color(blue)(-1)`

Explanation:

Factoring the left side of `2h^2-h-3=0`
`color(white)("XXX")(2h-3)(h+1)=0`

which implies

either
`color(white)("XXX")(2h-3)=0color(white)("XX")rarrcolor(white)("XX")h=3/2= 1 1/2`
or
`color(white)("XXX")(h+1)=0color(white)("XX")rarrcolor(white)("XX")h=-1`