Question

How do you solve `2Ln(x(18)+1)=2.3`?

Answer 1

`x=0.12`

Explanation:

As `2ln(x(18)+1)=2.3`

`ln(18x+1)=2.3/2=1.15`

`18x+1=e^1.15=3.1582`

`therefore 18x=2.1582` and

`x=2.1582/18=0.12`