Question

How do you solve `2log_3(x+4) - log_3 243 = 2`?

Answer 1

I got: `x=3^(7/2)-4=42.7654`

Explanation:

We use the definition of log to get:
`log_3(243)=5`
so we write:
`2log_3(x+4)-5=2`
`2log_3(x+4)=5+2`
`2log_3(x+4)=7`
`log_3(x+4)=7/2`
`x+4=3^(7/2)`
`x=3^(7/2)-4=42.7654`