Question

How do you solve `2m-17=21`?

Answer 1

`m=19`

Explanation:

Isolate 2m by adding 17 to both sides of the equation.

`2mcancel(-17)cancel(+17)=21+17`

`rArr2m=38`

To solve for m, divide both sides by 2

`(cancel(2) m)/cancel(2)=38/2`

`rArrm=19`

`color(blue)"As a check"`

Substitute this value into the left side and if it is equal to the right side then it is the solution.

`m=19to(2xx19)-17=38-17=21=" right side"`

`rArrm=19" is the solution"`