How do you solve #2n^2-50=0#?

1 Answer
Mar 10, 2018

Answer:

See a solution process below:

Explanation:

First, add #color(red)(50)# to each side of the equation to isolate the #n# term while keeping the equation balanced:

#2n^2 - 50 + color(red)(50) = 0 + color(red)(50)#

#2n^2 - 0 = 50#

#2n^2 = 50#

Next, divide each side of the equation by #color(red)(2)# to isolate #n^2# while keeping the equation balanced:

#(2n^2)/color(red)(2) = 50/color(red)(2)#

#(color(red)(cancel(color(black)(2)))n^2)/cancel(color(red)(2)) = 25#

#n^2 = 25#

Now, take the square root of each side of the equation to solve for #n# while keeping the equation balanced. Remember, the square root of a number produces a positive and negative result.

#sqrt(n^2) = +-sqrt(25)#

#n = +-5#

The Solution Set Is:

#n = {-5, 5}#