How do you solve #2n ^ { 2} - 7n = 17#?

1 Answer
Nghi N
Jul 15, 2017

#(7 - 3sqrt13)/4#
#(7 + 3sqrt13)/4#

Explanation:

#y = 2n^2 - 7n - 17 = 0#
Use the quadratic formula in graphic form (Socratic, Google Search).
#D = d^2 = b^2 - 4ac = 49 + 68 = 117# ==> #d = +- 3sqrt13#
There are 2 real roots:
#n = -b/(2a) +- d/(2a) = 7/4 +- (3sqrt13)/4 = (7 +- 3sqrt13)/4#

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