How do you solve #-2n+3=8#?
1 Answer
Sep 19, 2016
Explanation:
Leave the n term and move numeric values to the right side of the equation.
subtract 3 from both sides.
#-2ncancel(+3)cancel(-3)=8-3#
#rArr-2n=5# to solve for n divide both sides by -2.
#(cancel(-2) n)/cancel(-2)=5/(-2)#
#rArrn=-5/2#
