How do you solve #-2r-6+r=3#?

1 Answer
May 6, 2018

Answer:

#r=-9#

Explanation:

#"collect terms in r on left side of equation and numeric"#
#"values on the right side"#

#rArr-r-6=3#

#"add 6 to both sides"#

#-rcancel(-6)cancel(+6)=3+6#

#rArr-r=9#

#"multiply both sides by "-1#

#rArrr=-9#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#(-2xx-9)-6-9=18-15=3#

#rArrr=-9" is the solution"#