# How do you solve 2s - 3t = 13 and 2s + 2t = -2?

Aug 22, 2015

The solutions are
color(blue)(s=2,t=-3

#### Explanation:

color(blue)(2s)−3t=13 ....equation $1$
 color(blue)(2s)+2t=−2.....equation $2$

Solving by elimination

Subtracting equation $1$ from $2$

cancelcolor(blue)(2s)−3t=13
$\cancel{\textcolor{b l u e}{- 2 s}} - 2 t = + 2$

$- 5 t = 15$
color(blue)(t=-3

Finding $s$from equation $2$
2s−3t=13
$2 s = 13 + 3 t$
$2 s = 13 - 9$
color(blue)(s=2