# How do you solve #2sin^2x-5sinx+2=0#?

##### 1 Answer

#### Explanation:

Use the substitution method and then factor

Let

so,

Now you can factor

Multiply the coefficient of the first term,

Ask yourself **what are the factors of #4# that add up to the coefficient of the middle term, #-5#**?

Factors of 4

Now place those factors in an order that makes it easy to factor by grouping.

Factor out **first** grouping.

Factor out **second** grouping.

Now you can factor out a grouping,

Now use the **Zero Property**

Now **switch back** to

**-1 and 1**.

Falling back to trigonometry

The side of length

All of that to say that

I have tutorials on methods of factoring found here, https://www.youtube.com/playlist?list=PLsX0tNIJwRTxqIIcfpsTII9_xhqVIbQlp