How do you solve #2sin(5x+4)=-sqrt(3)#?

1 Answer
Feb 3, 2015

Step by step.

Step 1:
Divide both sides by #2# to get #sin# without a nummber
#2sin(5x+4)=-root 2 3->sin(5x-4)=-1/2 root 2 3#

Step 2:
Take the #arcsin# of the expression at the right
(#arcsin# on your calculator will often look like #sin^-1#
and you use it with the Shift or 2nd button)

#(5x-4)=arcsin(-1/2 root 2 3)=?#

The question mark is because it is not clear whether you use degrees or radians. In both cases a number will come out.

Step 3:
Solve for #x#
#5x-4="number"->x=("number"+4)/5#