Question

How do you solve `2sin(5x)=-sqrt3`?

Answer 1

`x = pi/3 + (2kpi)/3`
`x = (2pi)/15 + (3kpi)/5`

Explanation:

Trig Table and unit circle -->
2sin 5x = sqrt3
sin 5x = sqrt3/2
Unit circle gives 2 solution arcs:
a. `5x = (2pi)/3 + (2kpi)`
`x = ((2pi)/15) + (2kpi)/5`
b. `5x = pi - (2pi)/3 = pi/3 + 2kpi`
`x = (pi)/15 + (2kpi)/5`