Question

How do you solve `2sin3x = sqrt(2)` on the interval [0,2pi)?

Answer 1

`x=pi/12 or x=pi/4`

Explanation:

let's write the equivalente form:

`sin3x=sqrt(2)/2`

the value `sqrt(2)/2` is assumed two times in the interval, when:

`3x=pi/4 or 3x=3pi/4`

so

`x=pi/12 or x=pi/4`